import java.util.*;public class Solution { public int solution(int n) { int answer = 0; while(n>0) { answer+=n%10; n/=10; } return answer; }}

SELECT a.title, a.board_id, b.reply_id, b.writer_id, b.contents, DATE_FORMAT(b.created_date, '%Y-%m-%d') AS created_dateFROM used_goods_board aJOIN used_goods_reply b ON a.board_id = b.board_idWHERE date_format(a.created_date,'%Y-%m')='2022-10'-- WHERE a.created_date BETWEEN '2022-10-01' AND '2022-10-31'ORDER BY b.created_date, a.title; 위에껀 MySQL아래껀 OracleSELECT a...

class Solution { public int solution(String s) { int answer = 0; answer = Integer.parseInt(s); if(s.charAt(0)=='-') { answer = '-'+answer; } return answer; }}부호도 고려해야되는 줄 알고 저렇게 if문 써서 했는데 Integer.parseInt(s) 함수는 문자열의 부호를 자동으로 인식해서 추가적인 부호 처리가 필요하지 않다고 합니다. class Solution { public int solution(String s) { int answer = 0..

class Solution { boolean solution(String s) { boolean answer = true; int p=0; int y=0; for(int i=0;i

class Solution { public long solution(int a, int b) { long answer = 0; if(ab){ for(int i=b; ia를 long타입으로 변환해줘야 에러가 안납니다..

class Solution { public int solution(String t, String p) { int answer = 0; long p1 = Long.parseLong(p); for(int i=0;i

select count(*) as fish_count from fish_info where year(time)=2021;

select id, length from fish_info order by length desc, id asc limit 10;